other exercises: 20241031_DiskMat_Serie6.pdf

Question for TA

Can you please correct all the tasks in this series? I have found the problems very difficult and I am not sure if my approach is correct

6.6 The hunt for Red October

inspiration: https://cage.ugent.be/~ldnaux/problem_5.html

The position of the submarine is

s(t)=s0+vt

Since s,v0∈Z are not known, the submarine has a par of unknown values (v,s0)∈Z×Z. Since Z is countable, Z×Z is countable as well (Theorem 3.22). The pairs can be written as

{(v1,s0,1),(v2,s0,2),…,(vn,s0,n)}

where t=1,2,…,n. At every t, Svetlana can fire a torpedo at

s(t)=s0,t+vtt

until she targets the position (pair) where the submarine is, e.g. t=n, thus sinking the submarine in a finite time.

6.5 Countability

For all l≥1,l∈N:

Al={f:N→{0,1}|∑i=0kf(i)≤kl+1 for all k∈N}

~~Since k,l∈N, kl+1 cannot be smaller than 1. Thus, all functions

f:N→{0,1}|∑i=0kf(i)≤1 for all k∈N

are also part of Al.~~
Now, we assume that Al is countable (Al⪯N). Let

b∈{0,1}∞andb=b0b1b2…g(b)=fbfb:N→{0,1}fb(x)={1bx=1 and ∑i=1x−1bx≤x−1l+10otherwise

Let b∈{0,1}∞ and x,k,l∈N. Since the function only returns 1 if ∑i=1x−1bx≤x−1l+1, the sum ∑i=0kfb(i) is always smaller than kl+1. Thus, fb is in Al.

-> This means that g(b)=fb∈S for b∈{1,0}∞

Let b,b′∈{0,1}∞ so that b≠b′. This means that bn≠bn′ for n∈N.
Let j be the smallest index where bj≠bj′.
Then fb(j)≠fb′(j), since only bj or bk′ satisfy the first case of the function.

-> fb is an injective function

We have shown that there is an injective function g:{0,1}∞→Al. According to Definition 3.42, then applies {0,1}∞⪯Al.

Since we assume that Al is countable and we have shown that {0,1}∞⪯Al it follows (Lemma 3.15):

{0,1}∞⪯Al∧Al⪯N⟹{0,1}∞⪯N

This is a contradiction, thus proving that Al is uncountable. ◻