links - IntML
Info

  • exam
    • multiple choice, fully on paper
  • projects
    • 3/4 have to "pass" to be able to do the exam
    • 1min video explaining solution for each project needed, uploaded to polybox
  • practice classes

Hilfsmittel IntroductionToMachineLearning

  • 2 A4 pages (1 sheet) handwritten / >11pt
  • calculator

Exercises

-> FS2026_tasks

Serie Lösung Korrektur

Vorlesung

#timestamp 2026-02-27

#todo completely useless - delete or rewrite

We have:

w^=ws+wpwsspan(X)=span(XX)

normal equation:

XXω=Xyω=(XX)Xy=Xy

#timestamp 2026-03-03

Variance might not be only because of noise, but also because there are not enough samples.

overfitting =^ too sensitive to noise

#timestamp 2026-03-04

-> increasing model complexity beyond point where training error =0, can lead to second decrease in generalization error (more than just u-curve)

splitting data

control model complexity
Complex model (e.g. high-degree polynomial) might make weights large / osscilate. To counteract:

  1. Smaller degree m
  2. Smaller number of monomials “active” by limiting l1-norm
  3. Limit l2 norm

Lasso Regression (1 Regularization)
Adds a penalty proportional to the absolute value of the coefficients.

w^lasso=argminw||yΦw||22+λ||w||1

Ridge Regression (2 Regularization)
Adds a penalty proportional to the square of the magnitude of coefficients.

w^ridge=argminw||yΦw||22+λ||w||22

Why Lasso Induces Sparsity

The geometric intuition lies in the shape of the constraint regions. The 1 ball (a diamond/cross-polytope in 2D) has "corners" on the axes. When the elliptical contours of the least-squares loss function expand, they are highly likely to first hit the 1 ball at one of these corners, where one or more coordinates are zero.

Comparison Table

Feature Ridge (ℓ2​) Lasso (ℓ1​)
Penalty λwj2 $\lambda \sum
Solution Closed-form Numerical optimization
Sparsity No (coefficients 0) Yes (coefficients =0)
Use Case Preventing overfitting Feature selection

2026-03-04-3.0f

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